SEC-S20W3 Writing the first code

in #sec20w3sergeyk18 hours ago

I have always wanted to learn to program, and as such, I became so fascinated by programming. When the opportunity to learn to program in the Steemit Engagement Challenge season 20 presented itself, I held on to it and chose to participate in this course hosted by @sergeyk. I am here to perform homework Tasks for week 3, and I believe you will find this post interesting and informative.

Screenshot_20240927-232719_2.jpg


Choose your programming environment. Find and show 1) the code entry window, 2) the output window 3) the RUN button and 4) the data entry window - if you can't find this item, don't worry, I'll show you.


For this Task, I chose a C++ shell compiler. The compiler is user-friendly, and during my search for an online C++ compiler, I saw so many compilers, but I chose C++shell because no other students used it. From the above screenshot, I have indicated the entry window which I labeled 1, which is the first window by the top, which is for code writing. At the lower part, there's an output window which I labeled 2. Then, right between the entry window and output window, there's a run button, which I labeled 3. The data entry window is the same as the entry window.

During my research for the task, I found that some online compilers have separate data entry windows, compilers like one compiler.

iMarkup_20240927_104519.jpg


Find your way to act, from 1 to 100. Effective or not in this task is not important.


I have to solve this task in three versions, and I have to transverse my answer from 1 to 100 using only +1 and ×2. Here are the steps I took to reach from 1 to 100.

1+1+1+1+1+1=6×2=12×2=24×2=48×2=96+1+1+1+1=100

Narration of the steps;

  1. begin with 1

  2. add 1
    (1+1=2)

  3. add 1
    (2+1=3)

  4. add 1
    (3+1=4)

  5. add 1
    (4+1=5)

  6. Add 1
    (5+1=6)

  7. multiply by 2
    (6×2=12)

  8. multiplied by 2
    (12×2=24)

  9. multiply by 2
    (24×2=48)

  10. multiplied by 2
    (48×2=96)

  11. add 1
    (96+1=97)

  12. add 1
    (97+1=98)

  13. add 1
    (98+1=99)

  14. add 1
    (99+1=100)

It took me 14 steps to complete the task.


Find the best, shortest way. No one found it in the last lesson. Search!


So here I am trying to reduce the previous 14 steps I took in solving from 1 to 100 using only +1 and ×2. Let's see how it goes;

1+1+1=3×2=6×2=12×2=24×2=48×2=96+1+1+1+1=100

You can see that I have reduced my 14 steps to 12 steps by performing +1 for three times to have 3, then I performed ×2 for five times to have 96, and finally, I performed +1 for four times to have 100. I thought of another shorter step than this one, and I came up with this;

1+1+1= 3×2= 6×2= 12×2= 24×2= 48+1+1=50×2= 100

From the above, I have reduced my steps to 10 steps and I found it's still very much I tried reducing it again, and I came up with the final one below;

1+1+1=3×2=6×2=12×2=24+1=25×2=50×2=100

This time it took me 9 steps to solve the problem as indicated above. This is how far I was able to reduce my steps.

This is the narration of the steps;

  1. Begin with 1.

  2. Add 1:
    ( 1 + 1 = 2 )

  3. Add 1:
    ( 2 + 1 = 3 )

  4. Multiply by 2:
    ( 3 x 2 = 6 )

  5. Multiply by 2:
    ( 6 x 2 = 12 )

  6. Multiply by 2:
    ( 12 x 2 = 24 )

  7. Add 1:
    ( 24 + 1 = 25 )

  8. Multiply by 2:
    ( 25 x 2 = 50 )

  9. Multiply by 2:
    ( 50 x 2 = 100 )


if in addition to +1and x2it is possible to create an additional variable int k;, how many steps will it save, you cannot k=n put a certain number in the variable, for example 7 or 23. You can only fix the value of the variable at a certain step n


I began operating with +1, then counted from 1 to 5, then stored it in the variable k, so k=5. Then again, I performed ×2 on 5 till I got 20. Finally, I multiplied the variable k by 20.

Here is the breakdown of the steps;

  • 1+1+1+1+1=5
  • set k=5
  • 5×2=10
  • 10×2=20
  • 20×k
  • 20×5=100

Screenshot_20240927-132120_1.jpg

  • I have a total of 21 followers

  • Concerning the requirement, I have added 21 which is the number to be added to 21 followers. So 21+21=42

  • Now it's time to break 42

I have to get to 42 starting from 1 using +1 and ×2. These are the steps I took to get to 42 on the first attempt;

  • 1+1+1+1+1=5( 5 steps)
  • 5×2=10(1step)
  • 10×2=20(1step)
  • 20×2=40(1step)
  • 40+1+1=42(2steps)

I arrived at 42 in 10 steps on my first attempt.

Here is the program(code)

#include <iostream> using namespace std; int main() { int a=1, count_operation=0; a=a+1+1+1+1; count_operation++; //5 a=a*2; count_operation++; //10 a=a*2; count_operation++; //20 a=a*2; count_operation++; //40 a=a+1; count_operation++; //41 a=a+1; count_operation++; //42 cout<<"I reached 42 from 1 in "<< count_operation <<" steps by using +1 and x2 commands"; return 0; }

I completed the program in 6 steps.

Screenshot_20240927-143208_1.jpg


Take your number, I take my 49 and add its digits and also add 7: 4+9+7=16
We need to write a program to raise the number to the 16th power - all of you will have different numbers.


I have taken my number which is 42, then added its digits and also added 7, then I have;
4+2+7=13. I am going to write a program of 4^13, where 4 is the base and 13 is the power. Here is the program;


#include <iostream> using namespace std; int main() { int a=4*4*4*4*4*4*4*4*4*4*4*4*4,pow; // 4^13 pow=a*a; // 4^3 pow=pow*pow; // 4^6 pow=pow*pow; // 4^9 pow=pow*pow; // 4^12 pow=pow*pow; // 4^13 cout<<a<<"\n"; return 0; }


Screenshot_20240927-161516_1.jpg

The program runs successfully, and 4^13=67,108,864.


Write a program to divide it into numbers. And now how to collect it from numbers back into a number? How to reverse a number. In other words, unfold. for example, how to get 39 from 93.


Again, I chose my number of followers, that is 21, and then I will write a program to divide it into 2 and 1. Here is the program;

#include <iostream> int main() { int number = 21; int onesDigit = number % 10; // Units int tensDigit = (number / 10) % 10; // Dozens std::cout << "Units Digit: " << onesDigit << std::endl; std::cout << "Tens Digit: " << tensDigit << std::endl; return 0; }

Screenshot_20240927-192826_1.jpg

To separate the number, I used integers separation or division / and module %


Take the first three numbers from your profile (the number of followers or posts) - divide it into numbers.


I took the first three numbers from my number of posts, which is 102, and I am going to divide the numbers with a program. Here is the program;

#include <iostream> int main() { int number = 102; int onesDigit = number % 10; // Units int tensDigit = (number / 10) % 10; // Dozens int hunsDigit = (number / 100) % 10; // Hundreds std::cout << "Units Digit: " << onesDigit << std::endl; std::cout << "Tens Digit: " << tensDigit << std::endl; std::cout << "Hundreds Digit: " << hunsDigit << std::endl; return 0; }

Screenshot_20240927-194920_1.jpg

I saved or stored 102 in the number variable. Then, hundredths, tenths, and units are extracted using arithmetic operators, as seen in my program.


Find a four-digit number in your profile (by writing out the first digits, or combining it with others, the first two of one and the first two of another.) Or a random number - the main thing is that it is not in other homework. Divide it into numbers - the first number is X, the second number is X, the third number is X, the fourth number is X


I chose the total number of my posts, which is 1028, and wrote a program to divide them into numbers, such that all the numbers will be x. Here is the program;

#include <iostream> int main() { int number = 1028; int onesDigit = number % 10; // Units int tens digit = (number / 10) % 10; // Dozens int hunsDigit = (number / 100) % 10; // Hundreds int thouthDigit = (number / 1000) % 10; // Thousands std::cout << "First digit (x): " << onesDigit << std::endl; std::cout << "Second digit (x): " << tensDigit << std::endl; std::cout << "Third digit (x): " << hunsDigit << std::endl; std::cout << "Fourth digit (x): " << thouthDigit << std::endl; return 0; }

Screenshot_20240927-232719_1.jpg

I saved or stored the number 1028 in the number variable. Then I converted the number into the digits using the arithmetic operations.

First digit: number / 1000
Second digit: (number / 100) % 10
Third digit: (number / 10) % 10
Fourth digit: number % 10

Then we have the divided numbers as seen in the above image.

I invite;
@goodybest
@eliany
@blessedbee

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