You are viewing a single comment's thread from:RE: 9 /View the full contextthatgermandude (59)in #math • 7 years ago I believe you but I still want the proof of that formula :3
The standalone b's cancel in (n - 1) · b + (b - n) and that's that.
ah right, nb-b+b-n is the same as nb-n. Didn't see that, thanks