“SLC-S22W5//Polynomial and rational expressions”
The last time I applied for this, I could remember I didn't do well. So, I decided to apply again. I love mathematics very much and no matter how difficult the problem be, I would try all my possible best to get it right. Even if this won't favour me, I would keep on trying.
Greetings to @khursheedanwar. I've always enjoy your kind of work, even though some questions here seems critical.
That's Mathematics for me
Task 1
S/N | Polynomial Expressions | Rational expressions |
---|---|---|
1 | From your teachings Sir, Polynomial expressions is an algebraic expression that contains variables, coefficients as well as mathematical terms. | Rational expressions is an algebraic expression comprising of two polynomial expression. |
2 | Polynomial expressions term may be added, subtracted and multiplied but they can't be divided | Rational expression can be added, subtracted, multiplied and also divided |
Example of Polynomial expressions: 2x²+3x–4
Examples of Rational expression: (2x²+1) / (x–2) = 3
General forms for rational expressions:
(2x+1) / (x–2) = 3
First you have to cross multiply the equation
2x+1 = 3(x–2)Simplify the equation
2x+1 = 3x–6Isolate for x;
3x–2x = 1 + 6
x = 7.
General forms for Polynomial equations:
x² + 4x – 5 = 0
Factorize the polynomial
x² + 4x – 5 = (x+5)(x–1) = 0Set each factor equivalent to zero
x+5 = 0, or x–1 = 0Solve for x, making x the subject of the formula:
x = —5 or 1.
Task 2
- Factoring of numerator and denominator
This is the first step in simplifying a rational expression. Here, both the numerator and the denominator is factorized in their prime factors.
- Cancellation of common factors
This is the second steps. It involve cancelling common factors in between numerator and denominator. For example: 3(x+6) / (x+6) = 4
The common factors is (x+6). And if it is cancelled out, what is left is 3 = 4.
- Writing of simplified expression:
At this points, the simplified expression is written out.
Factors required to be cancel are:
Common factors such as:
2(x+2) / (x+2) = 2
The common factor (x+2) can be cancelled out.
After cancelling, this is what we have:
2 = 2.
- 3x² + 2x + 1
Factorize
(3x–1)(x+1) = 0
Set each factor equivalent to zero
3x–1=0 or x+1=0
Solve for x
x = ⅓ or x = –1
- 2x²–x–3
Factorize
(2x+3)(x–1)
Set each factor equivalent to zero
2x+3=0 or x–1=0
x=–3/2 or 1
- Scenario number 1:
x²+5x+2
Factorize
(x+2)(x+3)
Set each factor equivalent to zero
x+2=0 or x+3=0
Therefore, x=–2 or –3
- Scenario number 2:
Total harvest (tH) = tons of wheat / tons of barley
= x/3x
Cross multiply
tH = 3x–x+4=0
Simplify the above expression of tH
3x–x=2x
This implies that; 2x+4 = 2(x+2) = (x+2)(x+2) = 0
x+2 = 0
Therefore, the value of x = –2.
https://x.com/savi567/status/1879600151867920827
Well done bro you have done and explain well I wish you da best
Thankyou