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RE: #Chemistry Challenge 6
A
1: for time
no of bees = 40,000
in a 20 day period the weight of honey produced by them = 360000 g
using the direct relation between time and wt, we get 1/36 day = 24/36 hr = 40 min
2: for no of moles
mass percentage of glucose= 80%of37.5%of500= 150g of glucose
no of mols= 150/180= 0.833 mol
no of molecules= 150/180* Avogadro's number= 5.091*10^23 molecules
B
volume of cylinder = pir^2h where r=0.04m
density = mass/volume = 1249.96 kg/m3
C
From Hess's law
Energy released when 1 mol of glucose is burned is -2808.4 KJ
since, 1/10th of honey is equivalent to 15 g of glucose, using the simple unitary method we get -234.033 KJ
Apart from the number of molecules that looks really good! However, some other Steemians were faster this time! :)
I hope you enjoyed the competition nevertheless!
Yeah i did. Thank you for encouraging this kind of posts. TBH, i dont know how to use the power function here, so just used raised to the '^'
You can write it by using <sup>text</sup>
For example: 1023
Thank you :). And about the number of molecules, i was contemplating till now and realized what you meant. But here in our country, we're taught that the base of Avogadro's no is 6.023 and not 6.022. This was in high school and it's still embedded in me. And again Thank you and will keep an eye out for your contests. CHEERS!