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RE: #Chemistry Challenge 6
Opus I forgot that was 1/10 of the honey. So I edit add a few line here:
Consumed honey = 50 gram = 15 gram glucose = 0.0833333 mole =
so ΔHR = -234 kJ
Opus I forgot that was 1/10 of the honey. So I edit add a few line here:
Consumed honey = 50 gram = 15 gram glucose = 0.0833333 mole =
so ΔHR = -234 kJ
Right! So @jedigeiss 'stole' you this part of the solution because he was faster! :)
Well done nevertheless - hope you enjoyed the competition! (I will send you 3 STEEM.)
Haha !! That was really fun!!! This is probably the first time for me to work on a Hess cycle in the recent five years. Really took me some time back to the definition and make sure I didnt remember things wrongly XDD