"SLC-S22W6//Graphing and conic sections."

in #algebra-s22w611 hours ago

Steemian Friends,
Today, I will submit the homework for the @khursheedanwar Brother lesson in Week 06 of Steemit Learning Challenge 22. The lesson name is SLC S22W6//Graphing and Conic sections. I have loved Mathematics since childhood. It is my favourite subject. I hope everyone likes my homework.

Graphing and Conic sections.png
Design By Canva


Task-01


Differentiate between quadratic and exponential functions with examples and general forms of each!

Quadratic function:
A quadratic function is a polynomial function whose degree is 2. General form of quadratic function is f(x)= ax^2+bx+c,
Where a,b, & c are real numbers, and a is not equal to 0.

Example:
f(x)=3x^2+5x+3 is a quadratic function.

Where,
a=3
b=5
c=3
The degree is 2.

Exponential function:
We use the Exponential function to calculate population growth or decline, compound value and interest rate.
The general form of the exponential function is f(x)=ab^x
where, a= Initial Value
b= base
x=Exponent.

Here,
a is not equal to zero, and
b is not equal to 1
b>0.

Example:
f(x)=50(5.6)^x is an exponential function.


Differences:


AspectQuadratic FunctionExponential Function
General Formf(x)= ax^2+bx+cf(x)=ab^x
Examplef(x)=3x^2+5x+3f(x)=50(5.6)^x
SymmetricQuadratic Function is symmetric about vertexExponential Function no symmetry
GraphQuadratic Function is parabolaExponential Function is curved

Task-02


Provide real world examples of exponential functions and quadratic functions (Minimum 2 for each)that are not discussed in class!

Here, I give two real-world examples of exponential and quadratic functions:


Exponential function:

Population Growth:
If the population of a country doubles every 10 years, the number of people P(t) over time (t) can be calculated as:

IMG20250122140254.jpg

Radioactive decay:
We know that the amount of radioactive material decreases with time. For example, the mass M(t) after time t can be expressed as:

IMG20250122151747.jpg

Projectile Motion:
If I throw a ball upwards, the quadratic function against the force of gravity will be as follows. Here, the initial height acts as a gravitational force over time.

IMG20250122152048.jpg

Revenue Optimization:
I can write the price increase of a company's product rod as a quadratic function. Here, x is the price of the product. In the picture, I have shown it as a function.

Task-03


• Please find out equation of the circle with center (2, 3) and radius 4.

First, we know the equation of the circle, write (x-h)^2+(y-k)^2=r^2.

Then, the centre of the circle (h,k)=(2,-3) and radius r=4 in the above equation of a circle.

IMG20250122152304.jpg

Then, by algebra, I get an equation, which is the equation of the circle. x^2+y^2-4x+6y=3.


• Please solve for x: 2x^2 + 5x - 3 = 0

I will solve the given equation using a quadratic formula.
The quadratic formula, x=-b+/-√b2-4ac/2a

Here,
a=2
b=5
c=-3
Substitute the values ​​in the above equation.

IMG20250122152248.jpg

Then, doing algebra, I get two values ​​of x,
x=1/2 and -3.

Task-04


Scenario number 1


Suppose there's a satellite dish which is shaped like paraboloid.If equation of the paraboloid is given by y = 0.1x^2 then here x and y are measured in meters so now;


a) You need for graphing this equation.

The graphical equation is,
y= 0.1x^2 and is a parabola.
Vertex at the origin (0,0).
I have shown the graph below.

IMG20250122184642.jpg

y=0.1x^2 is the parabola graph.
The parabola is a symmetric y-axis and opens upwards.


b) You need for finding out focal length of paraboloid.

IMG20250122170050.jpg

We know,
Parabola general form is, y=1/4f x^2.
Given the equation, y=0.1x^2.
I put the value of y into the parabola equation and get the focal length,
f= 2.5 meters.


c) You need for finding out equation of directrix.

The directrix for the parabola opening upwards is the horizontal line,
y= -f,
where,
f= focal length.

IMG20250122170934.jpg


Scenario number 2


You need for suppose that there's a ball which is thrown in upward direction from ground with an initial velocity of 50 ft/s.Suppose if height of ball above ground is given by the equation h(t) = -16t^2 + 50t and here t is presenting time in seconds then;


a) You need for graphing this equation.

I have graphed the equation h(t)=-16t^2+50t. Before plotting each graph, I had to solve for b and c. The graph shows that the ball took 1.56 seconds to reach 39.06 feet, and the ball hit the ground in 3.125 seconds.

IMG20250122192110.jpg


b) You need for finding out maximum height reached by this ball.

We know,
The Parabola vertex equation formula is t= b/2a
where,
a= -16
b=50,
Put the value of a and b in the above equation, t= 1.5625.
Now, put the value of t into the equation,
h(t)= -16t^2+50t and do the algebraic calculation.
Then I get the height of the ball h(t)= 39.06 feet.Ans:

IMG20250122190317.jpg


c) You need for finding out time which it is taking for ball for reach to ground.

I get the equation in question by algebraic calculation,
h(t)=-16t^2+50t=0
to get two values ​​of t,
namely t=0 and t=3.125 s.
I have shown these values ​​through graphs.

IMG20250122191301.jpg


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