Avent of Code - Day 10 - Cathode-Ray Tube
Advent of Code occurs at Dec 01 to 25 where each day, you will need to solve a puzzle. It is Festival and the problem statement is mostly related to Christmas.
Day 10 - Cathode-Ray Tube
https://adventofcode.com/2022/day/10
Q1
import sys
from collections import defaultdict
file1 = open(sys.argv[1], "r")
score = 0
def f(c):
return c in (20, 60, 100, 140, 180, 220)
data = defaultdict(int)
i = 0
while True:
line = file1.readline()
if not line:
break
i += 1
a = line.strip().split()
if a[0] != "noop":
print(a)
data[i + 1] += int(a[1])
i += 1
x = 1
for j in range(i + 1):
if f(j):
score += j * x
print(j, x)
x += data[j]
print(score)
Q2
import sys
from collections import defaultdict
file1 = open(sys.argv[1], "r")
score = 0
def f(c):
return c in (20, 60, 100, 140, 180, 220)
row = list("........................................")
data = defaultdict(int)
i = 0
while True:
line = file1.readline()
if not line:
break
i += 1
a = line.strip().split()
if a[0] != "noop":
data[i + 1] += int(a[1])
i += 1
x = 1
cur = row[:]
print(i)
for j in range(1, i + 1):
if j % 40 == 0:
score += j * x
print("".join(cur))
cur = row[:]
x += data[j]
if abs((j % 40) - x) <= 1:
cur[j%40] = '#'
print(score)
Getting interesting! Looking at Q1 - Huh? not much useful with only 2 instructions. Q2 - wow! Surprised to see how we make use of only 2 instructions to draw something meaningful using only ASCII characters.
I believe, similar questions have appeared in previous AOC (maybe 2020 or 2021).