Teil 9 der Serie

#HiermuesstejetzteingeilerHashtagstehen

⭐️ Deepseek, du bist raus!

⭐️ Es ist mal wieder soweit

Ein Kommentar der "etwas" länger wird. Nach Teil 8 nun Ausgabe 9.

Dieser Beitrag ist eine Antwort auf das Feedback zu meiner Wordl Lösung in der Community, die gar keine ist.

Nach dem Motto "Die Letzten werden die Ersten sein" habe ich das Wort 10 gewählt und mit dem Wort ALERT begonnen.

Resultat: A L E RT

Nun gut, zumindest 2 Buchstaben getroffen. Das T und das E sogar am richtigen Platz. Das ist doch mal ausbaufähig.

Zweiter Versuch: MEETS

Resultat: M EET S

No risk no fun. Das E ein zweites mal ins Rennen zu werfen war ein guter Move. Jetzt wird es einfach. Weil ich ja gerade mit Deepseek rum spiele und die No Community "NO rules - but a load of them!!" hat, könnte man ja auch mit "No cheat - No fun" mal die gefeierte KI befragen, ob sie diese Steilvorlage gebacken bekommt.

Let's go, Deepseek!

Witzig ist die Deep Think Funktion. Damit kann man die "Gedankenansätze" anschauen, wie die KI versucht die Fragestellung zu lösen.

Die läuft ungefähr so, wie wenn man ein eingehendes Fax im Oldschool Style Zeile für Zeile auf der Papierrolle mitlesen kann. Immerhin hat Deepseek knappe 6 Minuten benötigt, um verschiedene "Denkansätze" zu verfolgen, um zum Ergebnis zu kommen.

Here we go:

Okay, let me try to solve this Wordle puzzle. The user has given me some clues. The word is 5 letters long. The letters T, E, and E are included, but A, L, R, M, S are not. Also, the second letter is E, the third is E, and the fourth is T. So the structure is _ E E T _. The remaining letters need to be filled in.

First, I need to figure out the first and fifth letters. The known letters are E in position 2, E in 3, T in 4. The word looks like ? E E T ?. The letters T is already in position 4, so the T in the included list is accounted for. We need to make sure that the letters A, L, R, M, S are excluded from the remaining positions.

So the first letter can't be A, L, R, M, S. Also, the fifth letter can't be any of those. Let's think about possible 5-letter words that fit the pattern E E T in positions 2,3,4.

Possible first letters: Since the first letter can't be A, L, R, M, S, and it's the start of the word. Let's think of words starting with B, C, D, F, G, H, etc. Then the fifth letter also has to be a consonant since we already have E, E, T, and the fifth letter can't be E (unless duplicates are allowed, but Wordle usually allows duplicates if the letters are present multiple times. Wait, the included letters are T, E, E. So E is already present twice, so maybe the fifth letter is not E. But the user didn't specify that E is only in positions 2 and 3. Wait, the included letters are T, E, E, so there must be two Es and one T. But in the given structure, we have E in positions 2 and 3, which accounts for the two Es. So the fifth letter can't be E because that would make three Es, but the included letters only have two. So the fifth letter must be a different letter not in the excluded list and not E.

Wait, but maybe the user's included letters are T, E, E, meaning that the word has T and two Es. So positions 2,3,4 are E, E, T. So first and fifth letters must be letters that are not in the excluded list (A, L, R, M, S) and also not E or T (since T is already in position 4, but maybe T can be used again if allowed. Wait, the included letters are T, E, E, so the word must contain T once and E twice. So the T is already in position 4, so the fifth letter can't be T again. So first letter and fifth letter can't be A, L, R, M, S, E, or T. That leaves B, C, D, F, G, H, I, J, K, N, O, P, Q, U, V, W, X, Y, Z.

But the fifth letter must also not be any of the excluded letters. Let's brainstorm possible words. The structure is ? E E T ?. Let's think of words like "BEETH" – but that's not a real word. "BEETs" but S is excluded. "BEETN" – maybe "beet" is a root vegetable, but "beeten" isn't a word. Wait, "BEETH" isn't valid. How about "FEEET"? No, that's three Es and not a word. "DEETs" but S is excluded. "KEETS"? S is excluded. "KEETN"? Not a word. Wait, maybe "THEET"? No, H is allowed but does "theet" exist? I don't think so. "SLEET" has S and L which are excluded. "TWEET"? T is in position 1, but the structure is first letter unknown, then E, E, T. So TWEET would be T W E E T, which doesn't fit the structure. "SWEET" has S which is excluded. "FLEET" has L and E, but L is excluded. "GREET" has R which is excluded. "MEETS" has M and S, both excluded. "BEETS" has S. "NEETs" – S again. Wait, maybe "BEETH" is not a word. Hmm. Let's think again.

Wait, maybe the fifth letter is H. So the word would be something like ?EETH. Let's see. "BEETH" – no. "LEETH" – L is excluded. "FEETH" – maybe? Not a standard word. "TEETH" – T is in position 1 and 4, but the structure is ?EET?, so first letter would be T, making it T E E T ?, but the fourth letter is already T, so TEETH would be T E E T H. But then the T is in position 1 and 4. The included letters are T, E, E, so that's okay. But does TEETH fit the clues? Let's check:

Included letters: T, E, E – yes, TEETH has T and two Es. Excluded letters: A, L, R, M, S – none in TEETH. The structure: positions 2,3,4 are E, E, T. So TEETH would have position 2=E, 3=E, 4=T. Then position 1=T and position 5=H. But the user didn't mention T being in position 1. The included letters are T, E, E. So TEETH has two Ts, which would require that T is included twice. But the user's included letters only list T once. Therefore, TEETH would have two Ts, which might not be allowed if the included letters only mention T once. Wait, the user says "Enthalten sind: T, E, E" which translates to "Contained are: T, E, E". So the word must have exactly T once, and E twice. But TEETH has two Ts and two Es, so that's invalid. Therefore, TEETH is not the answer.

Da haben wir das Denkproblem

Ich habe nicht behauptet, dass das T nur einmal vorkommt.

Hmm. Then maybe the fifth letter is N. So ?EETN. Like "BEETN"? Doesn't make sense. Or "KEETN". Not a word. What about "MEETN"? M is excluded. "PEETN"? No. "WEEN" is four letters. Wait, maybe "WEEN" but that's four letters. Not helpful.

Wait, maybe the fifth letter is D. So ?EETD. "BEETD"? No. "DEETD"? No. Maybe "FEETD"? No. Not a word.

Wait, maybe the fifth letter is a vowel other than E. The excluded vowels are A, but others like I, O, U are possible. Let's see. For example, "BEETI"? Not a word. "BEETO"? Like "beeto"? Not standard. "BEETU"? No. Hmm.

Alternatively, maybe the first letter is a consonant and the fifth is a consonant. Let's think of words like "KEETS" but S is excluded. "KEETN" as before. "JEETZ"? Not a word. "WEETT"? W in first position, but then T is in fifth, but that would be W E E T T, which has two Ts. But the included letters only have one T. So that's invalid.

Wait, maybe the fifth letter is C. "BEETC"? No. "MEETC"? M is excluded. "FEETC"? No.

Alternatively, maybe the first letter is B. So B E E T ?. "BEETH" is not a word. "BEETS" has S. "BEETL" – L is excluded. "BEETB"? No. "BEETO"? Not a word.

What about "DEET"? That's four letters. "DEETS" has S. "DEET" with an extra letter? Not sure.

Wait, maybe the word is "BELLE" but that has L which is excluded. "BETEL" has L. "BEVEL" has L. Not helpful.

Wait, maybe the word is "EERIE" but that's E in position 1, which we don't have. The structure is ?EET?, so first letter is unknown. "EERIE" doesn't fit.

Wait, maybe the first letter is H. So H E E T ?. "HEETH"? Not a word. "HEETS" has S. "HEETL" has L. "HEETT" – double T, but included letters have only one T. So invalid.

Alternatively, "CHEET" – but that's part of "cheetah". "CHEET" isn't a word on its own. Plus, if C is the first letter, then C H E E T? No.

Wait, maybe "THEFT". Let's check: T in position 1, but structure is ?EET?. So T H E F T – no, structure is T H E F T, which doesn't match E in position 2,3. Wait, no. THEFT is T H E F T. So position 2 is H, which contradicts the clue that position 2 is E. So no.

Wait, maybe "SWEET" but S is excluded. So that's out.
Wait, "BEETLE" is six letters. "BEET" is four letters. Hmm.
Wait, maybe "BEET" with another letter. But the word has to be five letters. Let's think of other possibilities. Maybe "MEETs" but M and S are excluded. "KEEN" is four letters. Not helpful.
Wait, maybe the fifth letter is K. So ?EETK. Not a standard word.
Wait, maybe "BEETN" isn't right. Let me think differently. Maybe I'm missing something. The structure is EET. So the word ends with T and the fifth letter. Let's think of words ending with "EET" plus a letter. For example, "TWEET" is T W E E T, which would be T in position 1 and 5. But the structure is ?EET?, so the fourth letter is T. So TWEET would be T W E E T, which doesn't fit because the fourth letter is E, not T. So that's not it.

Wait, perhaps "BEET" as the first four letters, then a fifth letter. But "BEET" is four letters. Adding a fifth letter, but without using excluded letters. "BEETH" – not a word. "BEETS" – S is excluded. "BEETZ"? No. Hmm.

Wait, maybe the word is "TEETH" but we already ruled that out because of two Ts. Unless the included letters allow for two Ts. Wait, the user says "Enthalten sind: T, E, E" – which translates to "Contained are: T, E, E". So the word must include T once and E twice. If the word is TEETH, that's T, E, E, T, H – so two Ts, which would mean the included letters should list T twice. But the user only listed T once. Therefore, TEETH is invalid.

Hmm. Maybe I'm missing a word here. Let me think again. The structure is EET. So the first letter is unknown, then E, E, T, then another letter. Let's think of possible letters for the first and fifth positions.

Possible first letters (excluding A, L, R, M, S, E, T): B, C, D, F, G, H, I, J, K, N, O, P, Q, U, V, W, X, Y, Z.

Possible fifth letters (same exclusions): B, C, D, F, G, H, I, J, K, N, O, P, Q, U, V, W, X, Y, Z.

So combinations could be:
B E E T H – "BEETH" – not a word.
B E E T N – "BEETN" – no.
C E E T H – "CEETH" – no.
D E E T H – "DEETH" – no.
F E E T H – "FEETH" – no.
G E E T H – "GEETH" – no.
H E E T H – "HEETH" – no.
K E E T H – "KEETH" – no.
N E E T H – "NEETH" – no.
P E E T H – "PEETH" – no.

Wait, perhaps "FEET" with a fifth letter. But "FEET" is four letters. "FEETS" – S is excluded. "FEETED" is six letters.
Wait, maybe the word is "BEENT" – no, that would have N in the fifth position. B E E N T. But the structure requires the fourth letter to be T, so BEENT is B E E N T – the fourth letter is N, which doesn't match. So that's not right.

Alternatively, "BEEST" – but S is excluded. "BEEST" would be B E E S T – S is excluded, so no.
Wait, "BEECH" – but that's B E E C H. The fourth letter is C, not T. Doesn't fit.
"BEEFS" – S is excluded. "BEEFY" – fourth letter F, not T.
"BEETLE" is too long.
Wait, maybe "MEETING" is too long. Not helpful.

Hmm. This is tricky. Maybe I need to consider that the fifth letter could be a vowel like O or U. Let's try:
B E E T O – "BEETO" – not a standard word.
F E E T O – "FEETO" – no.
D E E T O – "DEETO" – no.
G E E T U – "GEETU" – no.

Wait, maybe "YETI" is four letters. Not helpful.

YETI?! Nee, nicht wirklich hilfreich. #lol

Alternatively, "EETEN" – but starts with E, which would make the first letter E, but the structure allows for any first letter except excluded ones. Wait, the first letter could be E, but the included letters already have two Es. However, the user's included letters are T, E, E, so the word must have exactly two Es and one T. If the first letter is E, then the word would have three Es, which is not allowed. Therefore, the first letter cannot be E. So E is excluded from the first and fifth letters.

Therefore, first and fifth letters must be consonants not in the excluded list. Let's try to think of less common words. Maybe "THEET" – but does that exist? Let me check. "Theet" might be a variant spelling, but I don't think it's a standard English word. Maybe "KEETS" but S is excluded. "KEET" is a bird, but that's four letters. "KEETO" – adding O, but not a word.

Wait, maybe "BEET" with a D at the end? "BEETD" – no. "BEETE" – but fifth letter E would make three Es. Not allowed.

Auch diese Behauptung, ein drittes E wäre nicht erlaubt, habe ich nie aufgestellt.

Go ahead, dumbass!

Wait, maybe "TEPEE" – but that's T E P E E. The structure doesn't match. The fourth letter should be T, but in TEPEE it's P.

Alternatively, "TEETH" – already considered. Two Ts, which conflicts with the included letters.

Tut es doch gar nicht. Wenn ich die beiden fehlenden Buchstaben kennen würde, bräuchte ich dich nicht fragen.

Wait, perhaps the word is "TWEET" but as discussed earlier, the structure is T W E E T, which would have the fourth letter as E, not T. So no. Alternatively, "EXERT" – but E is in position 1, and R is excluded. So no.
Wait, "EJECT" – but J is allowed, but E in first position. Structure is E J E C T – positions 2 is J, which should be E. So no.

Hmm. Maybe I need to think of a less common word. "BEVET" – no, that's a term in heraldry, but not common. "BEVET" would be B E V E T – positions 2 and 3 are E and V, which doesn't fit.

Wait, "BETEL" – has L, which is excluded.
Wait, "FETED" – no. "FEEDS" – S is excluded.
Wait, "JEELS" – S and L excluded. Not helpful.
"NEEDS" – S excluded. "NEEDY" – fourth letter D, not T.
"PEETS" – S excluded. "PEET" – four letters.
"SEETH" – S excluded.
"TEEMS" – S excluded and M is also excluded.
"WEETs" – S excluded.

Wait, maybe "BEET" is part of the word, but I'm stuck. Maybe the answer is "BEETH" even if it's not a standard word? But Wordle usually uses common words.

Wait, maybe I'm missing something. Let me check the structure again: positions 2,3,4 are E, E, T. So the word is ?EET?. The fifth letter can't be E or any excluded letters. Let's think of all possible fifth letters allowed:

Possible fifth letters: B, C, D, F, G, H, I, J, K, N, O, P, Q, U, V, W, X, Y, Z.

Now, combining with possible first letters (same list). Let's try to find a combination that makes a real word.

For example:
B E E T H: BEETH – not a word.
C E E T H: CEETH – no.
D E E T H: DEETH – no.
F E E T H: FEETH – no.
G E E T H: GEETH – no.
H E E T H: HEETH – no.
K E E T H: KEETH – no.
N E E T H: NEETH – no.
P E E T H: PEETH – no.
W E E T H: WEETH – no.

What about fifth letter being O:
B E E T O: BEETO – not a standard word.
F E E T O: FEETO – no.
Fifth letter U:
B E E T U: BEETU – no.
Fifth letter N:
B E E T N: BEETN – no.
K E E T N: KEETN – no.
Fifth letter D:
B E E T D: BEETD – no.
Fifth letter Y:
B E E T Y: BEETY – no, but "beet" is a root vegetable, so "beety" could be an adjective, though it's not commonly used. Maybe in some contexts. Would Wordle accept that?

Alternatively, "BEETY" – possibly. If that's considered a valid word. But I'm not sure. Let me check. "Beety" isn't in standard dictionaries, but might be slang or informal.
Alternatively, "BEETZ" – Z is allowed, but that's not a word.

Wait, maybe "BEET" with a silent letter? Not sure.

"BEET" with a silent letter? Come on. Was für ein Zeichen soll ich denn für einen stummen Buchstaben verwenden?

Wait, maybe the word is "THEED" – but that's T H E E D. Structure T H E E D – second letter is H, not E. So no.

Wait, "TEETH" was close but had two Ts. Maybe the user made a mistake? Or maybe I'm missing a word. Let me check again: the included letters are T, E, E. So the word must have exactly one T and two Es. TEETH has two Ts and two Es, so it doesn't fit. So it's invalid.

Tja, falsche Annahme. Alles muss man so einer KI im Detail erklären.

Wait, maybe the answer is "BELLE" but L is excluded. No.
Alternatively, "BEETE" – but that's three Es. Not allowed.
Wait, maybe "BEET" is the word but it's four letters. The user said 5 letters. So that's not.

I'm really stuck here. Maybe I need to consider that the first letter is W. So W E E T ?. "WEEKT" – no. "WEEKE" – E in fifth position, which would make three Es. "WEEKT" – no. "WEEKY" – no. "WEEKT" – K is allowed, but not a word.

Wait, "WEETT" – double T, but included letters only have one T. So invalid.
Wait, "TWEEZER" is too long. Not helpful.
Wait, maybe "BEET" with a K: "BEEKT" – K is allowed. B E E K T. But the structure requires the fourth letter to be T, which it is, but then the fifth letter is T again? No, "BEEKT" would be B E E K T. But the fifth letter is T. So that's two Ts, which isn't allowed. So no.
Alternatively, "BEEFT" – F is allowed. B E E F T. Fifth letter T. Again, two Ts. Not allowed.
Hmm. Is there a word I'm missing? Let me think of "EERIE" – no, structure doesn't fit. "EJECT" – no. "EXERT" – R is excluded. "EETEN" – but first letter E would add a third E. Not allowed.

Wait, "BEENT" – B E E N T. The fourth letter is N, not T. So no.
"BENTO" – no. "BETTY" – T is duplicated, but structure is wrong.
Wait, maybe "BEETLE" but it's six letters. No.
Alternatively, "BEET" as a root, but not five letters. Maybe "BEETS" but S is excluded. "BEETROOT" – too long.
Wait, maybe "BEET" with a H at the end: BEETH. Even if it's not a standard word, could it be the answer? But I think Wordle uses common words. So maybe the answer is a less common word I'm not thinking of.

Alternatively, maybe the first letter is K. K E E T ?. "KEETS" – S excluded. "KEET" – four letters. "KEETO" – no.

Wait, "KEET" is a type of parrot, but that's four letters. Adding another letter, but S is excluded. "KEETA" – A is excluded. "KEETL" – L excluded. "KEETR" – R excluded. "KEETM" – M excluded. So no.

Wait, maybe "KEETO" – but not a word. "KEETN" – no.

This is really challenging. Let me try to look up 5-letter words with E, E, T in positions 2,3,4. Maybe there's a word I'm not thinking of.

After some research, I find that "BEETH" isn't a valid word. "THEFT" – structure doesn't fit. "SWEET" – S excluded. "TWEET" – structure doesn't fit. "BEETLE" – too long. "BEET" – four letters. "BEETS" – S excluded. "YETI" – four letters. "KEEN" – four letters. "BEEN" – four letters. "BEETY" – maybe informal. "BEET" with a Y. If "BEETY" is considered a valid word, maybe that's the answer. But I'm not sure.

Alternatively, maybe "BEET" with a D: "BEETD" – no. "BEETE" – three Es.

Wait, another approach: the word has to have letters T, E, E. Positions 2,3,4 are E, E, T. So the word is ?EET?. The fifth letter must be a consonant not excluded. Let me think of words ending with T followed by a consonant. Like "BEET" + consonant. For example, "BEETS" – S excluded. "BEETR" – R excluded. "BEETM" – M excluded. "BEETL" – L excluded. "BEETB" – no. "BEETC" – no. "BEETG" – no. "BEETH" – no. "BEETD" – no. "BEETK" – no. "BEETN" – no. "BEETP" – no. "BEETQ" – no. "BEETV" – no. "BEETW" – no. "BEETX" – no. "BEETY" – maybe.

If "BEETY" is a word, it would fit. But I'm not sure. Alternatively, maybe the answer is "BEVET" – but V is allowed. B E V E T – structure B E V E T. Positions 2 and 3 would be E and V, which doesn't match the required E and E. So no.

Wait, maybe "BEET" is part of a hyphenated word, but Wordle doesn't use those.

I'm starting to think that maybe there's a mistake in the clues, but assuming they are correct, the only possible word I can think of is "BEETY", even if it's not a standard word. Alternatively, maybe "FEET" with a letter, but I don't see it.

Wait, another angle: the word might be "THEFT", but let's check:
T H E F T – positions: 1=T, 2=H (should be E), so no. Doesn't fit.
"THETA" – A is excluded.
"THETE" – Hmm. "THETE" is a term from ancient Greece, but it's spelled T H E T E. So positions 1=T, 2=H (should be E), so no.
Wait, "TEPEE" – T E P E E. Positions 2=E, 3=P (should be E), so no.
"TEETH" – already considered.
"TWEET" – T W E E T. Positions 4=E, which should be T. No.
"BELLE" – L is excluded.
"BETEL" – L excluded.
"BEZEL" – L excluded.
"BEEFY" – F in position 4, not T.
"BEECH" – C in position 4, not T.
"BEECH" – no.
"BEEPS" – S excluded.
"BEEDI" – I is allowed, but structure is B E E D I – position 4=D, not T.

Hmm. I'm really stuck. Maybe the answer is a less common word like "EETEN" but that starts with E, which would make three Es. Not allowed.

Wait, maybe the first letter is F. F E E T ?. "FEETH" – no. "FEET" – four letters. "FEETD" – no. "FEETO" – no. "FEETU" – no. "FEETY" – no.
Wait, "FEET" is four letters. Adding a letter like "FEETUM" – too long. Not helpful.

I think I've exhausted all possibilities. The only word that fits the structure and letters is "BEETY", even if it's not a common word. Or maybe the answer is "THEFT" but that doesn't fit the position of Es. Alternatively, perhaps the answer is "BEET" with a typo, but it's four letters.

Wait, maybe the word is "BEET" with a silent H, making it "BEETH". Even though it's not a standard English word, maybe in another context. But I'm not sure. Wordle typically uses common words.

Alternatively, maybe the answer is "BEETLE" but it's six letters. No.
Wait, maybe the fifth letter is I. "BEETI" – no. "FEETI" – no.

I'm really not sure. Given the constraints, the only possible word I can think of is "BEETY", even if it's not widely recognized. Alternatively, perhaps "BEET" is the answer, but it's four letters. But the user specified five letters.

Wait, perhaps the answer is "BEET" with a space or apostrophe, but Wordle doesn't use those.
I'm stuck. Maybe I need to conclude that the answer is "BEET" but it's four letters, but the user said five. Hmm.

Wait, another thought: Maybe the fifth letter is a consonant that can follow "EET" to make a valid word. Like "BEETN" – but not a word. "BEETR" – R is excluded. "BEETM" – M excluded. "BEETL" – L excluded. "BEETK" – no.

Alternatively, maybe the answer is "BEET" with a double letter, but that doesn't add a fifth letter.
Wait, "BEET" plus a suffix like "S" but S is excluded. "BEETEN" – six letters.

I think I've tried all possibilities. The only possible word that fits the structure, even if it's not a standard word, is "BEETY". Alternatively, maybe the answer is "THEFT" but it doesn't fit the structure. Or perhaps the user made a mistake in the clues.

But assuming the clues are correct, the answer must be a five-letter word with E, E, T in positions 2,3,4, and no excluded letters. The only remaining option I can think of is "BEETY".

Um das englische 5-Buchstaben-Wordle zu lösen, nutzen wir die gegebenen Hinweise:
Enthaltene Buchstaben: T, E, E
Ausgeschlossene Buchstaben: A, L, R, M, S
Positionen: Buchstabe 2 = E, Buchstabe 3 = E, Buchstabe 4 = T

Die Struktur des Wortes ist somit: _ E E T _
Mögliche Kombinationen für die fehlenden Positionen (1 und 5) müssen die ausgeschlossenen Buchstaben vermeiden.

Nach Analyse der möglichen Buchstaben und Überprüfung gängiger Wörter ergibt sich:
Position 1: B
Position 5: Y

Das gesuchte Wort lautet BEETY.
Obwohl es kein weit verbreitetes Wort ist, passt es als mögliche (wenn auch unkonventionelle) Lösung in das vorgegebene Schema und die Bedingungen.

Resultat von Deepseek

Funfact

Mit einem registrierten Account speichert DS die verschiedenen Anfragen und man kann dort später wieder anknüpfen. Nachdem ich mich erfolgreich für TEETH entschieden habe dachte ich, OK, gib Deepseek noch eine Chance und einen Hinweis.

Ich: Falsch. Es ist nicht BEETY. Try again.

Deepseek: The server is busy. Please try again later.

OK, gfy AI #ROFL

Die Moral von der Geschicht' - Traue der KI schlicht nicht!

Die geht von Dingen aus, die weder ein- noch ausgeschlossen wurden. Tolle Aussichten für Ursulas Pre-crime AI. Viel Spaß auch.